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重写LinkedHashMap的toString方法,

来源: javaer 分享于  点击 48421 次 点评:13

重写LinkedHashMap的toString方法,


package com.aruisi.text;

import java.util.Arrays;
import java.util.Iterator;
import java.util.LinkedHashMap;
import java.util.Set;

class MyLinkedHashMap<K, V> extends LinkedHashMap<K, V> {

	private static final long	serialVersionUID	= 3070817484595053820L;

	@Override
	public String toString() {

		Set<java.util.Map.Entry<K, V>> keyset = this.entrySet();
		Iterator<java.util.Map.Entry<K, V>> i = keyset.iterator();
		if (!i.hasNext()) return "{}";
		StringBuffer sb = new StringBuffer();
		sb.append('{');
		for (;;) {
			java.util.Map.Entry<K, V> me = i.next();
			K key = me.getKey();
			V value = me.getValue();
			sb.append(key == this ? "(this Map)" : key);
			sb.append('=');
			sb.append(value == this ? "(this Map)" : value.getClass().isArray() ? Arrays.toString((Object[]) value) : value);
			if (!i.hasNext()) return sb.append('}').toString();
			sb.append(',').append(' ');
		}
	}
}

测试类

package com.aruisi.text;

import java.util.HashMap;
import java.util.LinkedHashMap;

public class Map {
	public static void main(String[] args) {
		HashMap<Object, Object> map = new LinkedHashMap<>();
		String[] string = new String[] { "s", "z", "", "5232" };
		Integer[] integer = new Integer[] { 1, 2, 4 };
		map.put("userId", "123");
		map.put("farmId", "3234");
		map.put("xxxId", "axsx");
		map.put("uuuId", "65657667");
		map.put("string", string);
		map.put("integer", integer);
		System.out.println(map.toString());
		MyLinkedHashMap<Object, Object> name = new MyLinkedHashMap<>();
		name.put("userId", "123");
		name.put("farmId", "3234");
		name.put("xxxId", "axsx");
		name.put("uuuId", "65657667");
		name.put("string", string);
		name.put("integer", integer);
		System.out.println("MyLinkedHashMap=" + name.toString());
	}
}


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