Java，

Java，

有点困惑了，try...catch...finally

 

我们在知道：finally不论在什么情况下都会执行。面对下面的代码，我有点困惑了，大家如果知道原因，指导指导。

 

public static void main(String[] args) {
		
		System.out.println("Hello World!");
		
		System.out.println(getValues());	
		
	}	
	
	
	private static int getValues(){
		int value = -1;
		try {
			value = 10 ;
			System.out.println(" value current1 in try is " + value);
			return value;
		} catch (Exception e) {
			value = 0 ;
			return value;
		}finally{
			value = 5 ;
			System.out.println(" value current2 in finally is " + value);
			
		}
	}

 

返回结果：

写道 Hello World!
value current1 in try is 10
value current2 in finally is 5
10

 

 

疑问 ：

      在finally中改变了value的值，为什么返回的值还是10？？？

 

如果在finally中也加上“return value;”，则返回结果如下：

写道 Hello World!
value current1 in try is 10
value current2 in finally is 5
5

 

如果将getValue方法修改如下：

	private static int getValues(){
		int value = -1;
		try {
			value = 10 ;
			System.out.println(" value current1 in try is " + value);
		} catch (Exception e) {
			value = 0 ;
		}finally{
			value = 5 ;
			System.out.println(" value current2 in finally is " + value);			
		}	
		System.out.println(" value current2 in getValues is " + value);
		return value;
	}

 

返回结果如下：

写道 Hello World!
value current1 in try is 10
value current2 in finally is 5
value current2 in getValues is 5
5
 

所以对于这个疑问，我无解了！！！

 

 

大哥大姐帮个忙解答解答！！！