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Android访问php取回json数据,androidphp取回json,运行说明其中http:/

来源: javaer 分享于  点击 15675 次 点评:33

Android访问php取回json数据,androidphp取回json,运行说明其中http:/


运行说明

其中http://10.0.2.2为Android访问本机url的ip地址。对应电脑上测试的http://127.0.0.1

另外执行代码时会抛出异常

java.net.SocketException: Permission denied

此为应用访问网络的权限不足 在AndroidManifest.xml中,需要进行如下配置:

<uses-permission Android:name="android.permission.INTERNET" />

就加在

</manifest>

之前就好了

然后测试通过。

php代码

$array = array(

'username'=>'杨铸',

'password'=>'123456',

'user_id'=>1

);

echo json_encode($array);

private void startUrlCheck(String username,String password){    HttpClient client = new DefaultHttpClient();    StringBuilder builder = new StringBuilder();    HttpGet myget = new HttpGet("<a href="http://10.0.2.2/Android/index.php">http://10.0.2.2/Android/index.php");    try {        HttpResponse response = client.execute(myget);        BufferedReader reader = new BufferedReader(new InputStreamReader(        response.getEntity().getContent()));        for (String s = reader.readLine(); s != null; s = reader.readLine()) {            builder.append(s);        }        JSONObject jsonObject = new JSONObject(builder.toString());        String re_username = jsonObject.getString("username");        String re_password = jsonObject.getString("password");        int re_user_id = jsonObject.getInt("user_id");        setTitle("用户id_"+re_user_id);        Log.v("url response", "true="+re_username);        Log.v("url response", "true="+re_password);    } catch (Exception e) {        Log.v("url response", "false");        e.printStackTrace();    }}//该片段来自于http://byrx.net
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